n^2+105n-1026=0

Solution for n^2+105n-1026=0 equation:

n^2+105n-1026=0

a = 1; b = 105; c = -1026;
Δ = b2-4ac
Δ = 1052-4·1·(-1026)
Δ = 15129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15129}=123$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(105)-123}{2*1}=\frac{-228}{2}
=-114
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(105)+123}{2*1}=\frac{18}{2}
=9
$